Enthuware

What will the following program print?

class Test{    
public static void main(String args[]){       
int k = 9, s = 5;       
switch(k){          
default :          
if( k == 10) { s = s*2; }
         else{             s = s+4;
            break;          }         
 case 7 : s = s+3;       
}       
System.out.println(s);    
}
}
Possible answers: 5 - 9 - 12 - It won't compile.

The correct answer is 9, but I marked 12 because I thought keyword break finished 'else' block but not 'default' block. So, if I will write for example:

default:
if(true){
if(true){
if(true){
if(true){
s=0;
break; <- do this Break finish default case too?
}}}}
s=12345; <- is this Dead code?

Thank you so much¡

1. Yes.
2. No, if(true) is a a special case that doesn't cause unreachable/dead code anywhere.

HTH,
Paul.

Hey! It's no break statement can be compiled in the else block!.. It must be fail to compile.

What happened when you actually tried to compile the given code? Observe that the break is inside the switch block.