About Question enthuware.ocajp.i.v7.2.1380 :

[NickWoodward]

int[][][] arr3 = {arr2};

so the brackets surrounding arr2 represent the third dimension of the array, and arr2 is a 2d element inside that dimension?

that is an evil question

Nick

[admin]

That is correct.

[Kevin30]

To simplify the principle, the following is a valid 2-dimensional array:

int[][] array2D = {{1,2}};

But what does it look like?
In trying out the code, I've figured out that:
array2D[0][0] = 1
array2D[0][1] = 2

But what about array2D[1]?
Is it null? It doesn't look like it. When I try to print it, I get a ArrayIndexoutofBoundsExeption.

[admin]

You get a ArrayIndexoutofBoundsExeption upon accessing array2D[1] because the length of array2D is 1. It has only one element, which is accessed through array2D[0].

array2D[0] points to an array of 2 elements i.e. { 1, 2 }. That is why when you do array2D[0][0], you get 1, and when you do array2D[0][1], you get 2.

HTH,
Paul.

[flex567]

The second answer, the correct answer is like this: int [] [] [] array3D = { { {0, 1}, {2, 3}, {4, 5} } };

Is this visual representation correct?

[admin]

Yes, your visual representation is correct.