About Question enthuware.ocajp.i.v8.2.1455 :

[dheeraj426]

What will the following code print?

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int x = 1; int y = 2; 
int z = x + +; 
int a = --y; 
int b = z--; 
b + = + + z; 
int answ = x > a? y > b? y:b:x > z? x:z; 
System.out.println( answ);

[admin]

What happened when you tried it out?
Also, please put code within

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.

[Sergey]

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int answ = (x>a) ? (y>b ? y:b) : (x>z?x:z);

I did not resolve this question at the paper. As for me, it is extremely hard question.

[OCAJO1]

What would you say is good exam taking strategy for time consuming questions like this, figure them out, or leave them for the end?

[admin]

If you are a beginner, then it does take some time to figure it out, so, better to leave it for the end.

[Nathan777]

I got pretty much this exact question with just different variable names on the exam today. Luckily, I just had it right before when I was taking this test at Panera Bread down the road from the testing center.

[brintal]

Is there any good strategy to quickly group the elements of nested ternary operators?

E.g. making

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x > a  ? (y>b ? y : b)  :  (x>z ? x : z)

out of

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x>a?y>b?y:b:x>z?x:z

EDIT: figured it out myself. This is a very good explanation: http://twistedoakstudios.com/blog/Post5 ... -operators

[admin]

Good link. thanks for sharing.

[SCOTTBART1]

Obtuse and deliberately muddy questions, don't see the point, nobody codes like that.

[admin]

It true that nobody codes like that but the exam does test your ability to parse through such code.