About Question com.enthuware.ets.scjp.v6.2.55 :

[TwistedLizard]

Regarding option 6

Short k = 9; Integer i = 9; System.out.println(k == i);

I understand the given reason why it won't compile, but the statement

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Short k =9;

mystifies me somewhat.
I know it actually does work, but the literal 9 is an int literal. So, why doesn't it box to an Integer which would be unassignable to a Short variable?

In the case of primitive assignments such as

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byte b = 9;

again 9 is an int literal, but I can make sense of the statement by imagining that the compiler inserts an implicit cast

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byte b = (byte)9;

Is the best way to think of it, that in this situation also, the compiler inserts a cast to short which is then boxed?

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Short k = (short)9;

[I manually created the subject as clicking on Discuss in the viewer brings up the wrong page.]

[admin]

Because section 5.2 of JLS clearly says:

A narrowing primitive conversion followed by a boxing conversion may be used
if the type of the variable is:
– Byte and the value of the constant expression is representable in the type byte

[TwistedLizard]

thank you