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Posted: **Wed Apr 14, 2021 10:52 am**

public static float parseFloat1(String s1) {
        try {
            return Float.parseFloat(s1);
        } catch (NumberFormatException e) {
            return 0.0f;
        } catch (IllegalArgumentException e) {
            return Float.NaN;
        }
    }

The correct answer is Calling parseFloat1("junk"); will return 0.0f. but I think it should be Calling parseFloat1("junk"); will return 0.0.
Indeed, there is a difference between returning(a float 0.0f) and actually printing(a float 0.0).
I am interested in your take on this matter.

Posted: **Wed Apr 14, 2021 11:56 pm**

0.0 is a double value. Why would it return 0.0 when the return type of the method is float?
Also, the return statement says return 0.0f;

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