Enthuware

Hi,
I correctly answred C, but I did it because I thought that I cannot switch over a boolean. In JLS (14.11): only char, byte, short, int, Character, Byte, Short, Integer, String, or an enum type are permitted.
This is confusing!

Not sure why you find it confusing. It is true that you cannot use boolean in a switch but that is not the case here anyway.
-Paul.

Hi,

Isn't a switch statement also not supposed to use the boolean data type ?

Thanks

That is correct. That is what I said above as well.
-Paul.

These questions is imposible to guess correctly since no book for preparation explains much about what does/doesn't compile.

Hi, I understand the code inside switch is unreachable but does switch itself cause a compile error without any case or default label? I actually implement this code by removing the "flag = true;" and it compiles ok. So switch doesn't cause a compile error. It is ok to has no case or default label and without any code inside the block?

Yes, if you have code inside a switch then that has to be associated with a case or default label. The explanation also explains the same.
Empty switch is fine as you already found out.

I thought it wouldn't compile cause variables i and flag are declared in the loop blocks and therefor not available outside of them.