Enthuware

Puzzled..
When using the "o" as the Regex in the examples, why does it not give 2 empty matches for the "o"'s in boo, when it gives 2 matches for the ones in foo?
For a string of "boo:and:foo" I would have expected the answer to be either:
{ "b", "", "", ":and:f", "", "" }
or
{ "b", "", ":and:f", "" }

Why is there a difference between boo and foo in this case?

Thanks

It doesn't give two blanks for boo because there is no blank after the second o. The second o is followed immediately by ":and:f". So there is only one blank between the two os.

In case of foo, there is nothing after the second o. That is why you see a second blank.

-Paul.

Oh right I see.
Thanks.

Regarding the following expression:
"boo:and:foo".split("o",0)

and the result:
String result[] ={ "b", "", ":and:f" }

Why result[1] is "", I was under the comprehension it was discarded due to the fact "" result are discarded.

Thank you.

When I execute "1 dan 2 dave 3 dick".split("\\d") I get a space in the beginning and then the rest of the result. If the split() is executed with a 0(zero) limit then how come there is leading space? 'm a bit confused about the leading space. how is it occuring?

Because as per the JavaDoc API of this method, only the trailing empty strings are not included in the resulting array.