Enthuware

I thought interface cannot be instantiated, but the correct answer for this question is "MyInterface i =c" where MyInterface is name of interface that the object c Class is implementing. How is this possible? I obviously missing smth out, something obvious :/

It is true that an interface cannot be instantiated but you are not instanciating any interface here. c points to an object of class C. So class C is instantiated (as given in the problem statement C c = new C();). Since C implements MyIFace, you can assign c to a reference of type MyIFace.

HTH,
Paul.

Thanks, Paul, that's explaining it. Cheers.