Enthuware

Hi Enthuware Admin and everybody.
I don't understand this answer "It will print Sum = 0".
Ok, variable sum is never changed but... isn't this a case of "unreachable code"?

int sum = 0;
for (int i = 0, j = 10; sum > 20; ++i, --j) // 1
{
sum = sum+ i + j;
}

At compile time sum = 0 and the condition to enter the for loop (sum>20) is not satisfied at the first iteration.
So the instruction sum = sum+ i + j; can never be executed.
Maybe compiler doesn't check the for loop statements or it doesn't check the variables value?
I'm confused, can someone help me?

Thank you so much.
G.

Compiler doesn't execute code so it can't evaluate variables. I can only look at compile time constants to see if some code is unreachable or not. That is why there is no compilation error for unreachable code.

Thank you.
It's clear now.