Enthuware

Consider the code

int x=3;
int y=++x * 5 / x-- + --x;
System.out.println(x+" "+y);

Is it true that post-increment takes precedence over pre-increment? If yes y should evaluate to 3. However, it evaluates to 7. Why?

Please post the source of the code.

Since the extension java is not allowed I copied-pasted the code

public class IncOpPrecedence {
public static void main(String args[]) {
int x = 3;
int y = ++x * 5 / x-- + --x;
System.out.println(x+" "+y);
}
}

By source, I meant the website or the book from where you got it.
In any case, no, post-increment does not have higher precedence than pre-increment. But precedence is not the only thing that governs the evaluation of an expression. Expression evaluation is governed by precedence as well as associativity. This article explains it nicely - http://cs-fundamentals.com/java-program ... tivity.php

HTH,
Paul.

Thank you for your reply.
The source is OCA: Oracle® Certified Associate Java®SE 8 Programmer by Jeanne Boyarsky and Scott Selikoff, Page 52, Table 2.1.