Enthuware

Regarding option 6

Short k = 9; Integer i = 9; System.out.println(k == i);

I understand the given reason why it won't compile, but the statement mystifies me somewhat.
I know it actually does work, but the literal 9 is an int literal. So, why doesn't it box to an Integer which would be unassignable to a Short variable?

In the case of primitive assignments such as again 9 is an int literal, but I can make sense of the statement by imagining that the compiler inserts an implicit cast Is the best way to think of it, that in this situation also, the compiler inserts a cast to short which is then boxed? [I manually created the subject as clicking on Discuss in the viewer brings up the wrong page.]

Because section 5.2 of JLS clearly says:

A narrowing primitive conversion followed by a boxing conversion may be used
if the type of the variable is:
– Byte and the value of the constant expression is representable in the type byte

thank you