Enthuware

Why does it fail to compile?

lambda expression does not create a new scope for variables.Therefore, you cannot reuse the local variable names that have already been used in the enclosing method

So e's scope is between the parentheses "(e, e->e.age<10000)" ?

Yes, you can try it out. Use the the variable specified in the lambda expression after the expression and see what happens.

this one is very funny cuz i answeared 'It will compile fine and print true when run.' but then i went back cuz i realized the question was too easy, like something is missing, the trickyness is missing, so ye i doublechecked and found lol