About Question enthuware.ocpjp.v11.2.3503 :

[mesginaa01]

public class TestOuter { public static class TestInner {
public void sayIt(){ System.out.println("hello"); } }
public static void main(String[] args){
//call here
} }

Why TestInner.sayIt(); cannot be the the second answer?

[admin]

As the explanation for this option says:

TestInner is static but its method sayIt is not. So, you need to do new TestInner().sayIt(); in main to invoke sayIt.

You can actually try it out.

[yuir12]

Hello, question:

new TestOuter.TestInner() -> are we using this call because TestInner is static? Thanks

[admin]

Yes, that is correct. Just like you refer to any other static member of a class.

[powerofviva]

Hi,

Code: Select all

public class TestOuter
{
   public static class TestInner
   {
       public void sayIt(){ System.out.println("hello"); }
   }
   public static void main(String[] args){
      //call here
      new TestOuter.TestInner() // ---> CLass or package is needed !!
   }
   
   public void tee() {

  new TestOuter.TestInner() // ---> even here compiler error, CLass or package is needed !!
 }
   
}

I am wondering how you did not get that error that I am getting! it even does not compile!

[powerofviva]

even your last answer does not compile:

TestInner.sayIt(); can be inserted in main.
TestInner is static but its method sayIt is not. So, you need to do new TestInner().sayIt(); in main to invoke sayIt.

inside static main method:
new TestInner().sayIt(); ---> TestOuter.this can not be referenced from statis method. so new TestInner() wont compile!

you have to call is inside non static method.

[admin]

The given answers and explanations are correct. Please read the options carefully.
BTW, you are missing a semi-colon in your code.

The last option indeed does not compile and that it why that option is an incorrect option.