About Question enthuware.ocpjp.v11.2.3140 :

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mikolajczak4
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About Question enthuware.ocpjp.v11.2.3140 :

Post by mikolajczak4 »

Hi,

I have one doubt in that answer.

Code: Select all

Double dVal = 0.0;
if((dVal = Double.parseDouble(str)) == iVal){ //2
== has precedence over = so the result of Double.parseDouble(str)) == iVal is boolean and it is assigned to dVal which is Double.

Do I miss something here ?

Thanks,
Wojciech

admin
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Re: About Question enthuware.ocpjp.v11.2.3140 :

Post by admin »

But there are parentheses involved. The expression dVal = Double.parseDouble(str) is surrounded by ( ). So, it has to be evaluated first. Operator precedence would have come into picture to resolve the ambiguity if all the terms of an expression were at the same level i.e.

dVal = Double.parseDouble(str) == iVal
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mikolajczak4
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Re: About Question enthuware.ocpjp.v11.2.3140 :

Post by mikolajczak4 »

my bad, thank you !

cjgiron
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Re: About Question enthuware.ocpjp.v11.2.3140 :

Post by cjgiron »

Hello Admin,

Will the actual test expect us to know how to parse numbers with the radix parameter?

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Re: About Question enthuware.ocpjp.v11.2.3140 :

Post by admin »

You will not need to convert or parse values but you may see a question that requires you to know that such a method exists.
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