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About Question enthuware.ocpjp.v11.2.3140 :
Posted: Tue Feb 23, 2021 2:17 pm
by mikolajczak4
Hi,
I have one doubt in that answer.
Code: Select all
Double dVal = 0.0;
if((dVal = Double.parseDouble(str)) == iVal){ //2
== has precedence over = so the result of Double.parseDouble(str)) == iVal is boolean and it is assigned to dVal which is Double.
Do I miss something here ?
Thanks,
Wojciech
Re: About Question enthuware.ocpjp.v11.2.3140 :
Posted: Tue Feb 23, 2021 6:05 pm
by admin
But there are parentheses involved. The expression dVal = Double.parseDouble(str) is surrounded by ( ). So, it has to be evaluated first. Operator precedence would have come into picture to resolve the ambiguity if all the terms of an expression were at the same level i.e.
dVal = Double.parseDouble(str) == iVal
Re: About Question enthuware.ocpjp.v11.2.3140 :
Posted: Sat Feb 27, 2021 12:09 pm
by mikolajczak4
my bad, thank you !
Re: About Question enthuware.ocpjp.v11.2.3140 :
Posted: Mon Sep 19, 2022 7:00 pm
by cjgiron
Hello Admin,
Will the actual test expect us to know how to parse numbers with the radix parameter?
Re: About Question enthuware.ocpjp.v11.2.3140 :
Posted: Tue Sep 20, 2022 9:43 pm
by admin
You will not need to convert or parse values but you may see a question that requires you to know that such a method exists.