Enthuware

It will compile and print 30.

But answer is mentioned as Compilation error.

Please make sure you have copied the code exactly as given.

This question is not correct, please review it. It gives no compilation error and as mentioned that interface's variables are never inherited and can be accessed only by the name of the interface class.

Again, the question and the given answer/explanation are correct. Copy the code exactly as given and try compiling it from the command line.

If Fruit declaration will be:
public class Fruit extends Food { //LINE1
then field 'types' in Food will hide 'types' in Eatable, so no problem.
But, when it is declared as:
public class Fruit extends Food implements Eatable { //LINE1
then in body of Fruit 'types' from Food has the same visibility scope as 'types' from Eatable - so, ambiguous reference will be.

how can i have compilation failure at line 1 and the following line

compiler only cares about the first error?

With questions that ask about compilation errors, you are expected to identify all errors that the compiler will notice when you try to compile the code.

Most problem statements use a standard format/style such as, "What will the following code print when compiled and run? ". But if you see multiple compilation issues, you should pick them all even if you think that the compiler will stop after encountering the first error.

thank you!