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Code: Select all

What will the following code print?


  int i = 0;
  int j = 1;
  if( (i++ == 0) [b]&&[/b] (j++ == 2) )
  {
     i = 12;
  }
  System.out.println(i+" "+j);

Code: Select all

This question is based on 2 concepts:

1. i = = ++j is not same as i = = j++;
In the case of i == ++j, j is first incremented and then compared with i. While in the case of i == j++;, j is first compared with i and then incremented.

2. The | operator, when applied for boolean operands, ensures that both the sides are evaluated. This is opposed to || which does not evaluate the RHS if the result can be known by just evaluating the LHS.

Now, let us see the values of i and j at each step:

int i = 0;
int j = 1;
if( (i++ == 0) [b]&[/b] (j++ == 2) )    //compare i with 0 and increment i => returns true and i becomes 1. Evaluate next condition:
		//compare j with 2 and increment j => return false and j becomes 2.
		//true & false returns false so i= 12 is not executed.
{
	i = 12;
}
System.out.println(i+" "+j)); //print 1 and 2