About Question enthuware.ocpjp.v7.2.1214 :

[The_Nick]

RESOLVED.

Hi,
So basically in short p1 must be the same as p2 in order to return true.
The name is quite confusing as it says startsWith, one would expect to check only the beginning
Forget about it checks only N elements belonging to the other path (the one passed as argument)
Thanks.

The_Nick.

[user_m1k0]

Output under Linux:

Code: Select all

\temp\records/clients.dat false

java --version
openjdk 21.0.5 2024-10-15
OpenJDK Runtime Environment (Red_Hat-21.0.5.0.11-1) (build 21.0.5+11)
OpenJDK 64-Bit Server VM (Red_Hat-21.0.5.0.11-1) (build 21.0.5+11, mixed mode, sharing)

improved code:

Code: Select all

public static void writeData() {
        // var p1 = Paths.get("\\temp\\records");
        // var p2 = p1.resolve("clients.dat");
        var p1 = Paths.get("temp", "records");
        var p2 = p1.resolve("clients.dat");
        System.out.println(p2 + " " + isValid(p2));
    }

[giginar]

Hello,

In the same test question 14's solution says "4. paths do not start or end with \." resolve method returns a Path object right, so why is this one returning a path that starts with "\". thanks.

[admin]

If you mean qid 2.1579 , the first line of the explanation clearly says - "Remember the following points about Path.subpath(int beginIndex, int endIndex)". So those 4 points are about the Path.subpath method. The Path object that this method returns does not start with \.