About Question com.enthuware.ets.scjp.v6.2.242 :

[TwistedLizard]

This seems sneaky!
According to the jls:

https://docs.oracle.com/javase/specs/jl ... ml#jls-3.8

a keyword cannot be used as an identifier, yet here is a snippet that does exactly that.

Code: Select all

class Test {

  public static void  doIt( String String )   // 1
  {
     int i = 10;
     i : for (int k = 0 ; k< 10; k++)    // 2
     {
        System.out.println( String + i); //3
        if( k*k > 10) continue i;        //4
     }
  }

  public static void main(String[] args){
    Test.doIt("X");
  }

}

I went straight for the
It will not compile because of line 1.
It will not compile because of line 3.
options.

[admin]

Why do you think it does exactly that?

[TwistedLizard]

public static void doIt( String String ) // 1

I'd read this as doIt() requiring a single parameter of type String using the variable name of String. I thought using a reserved word as an identifier was illegal.

However, I've just looked up the list of java's keywords. Although the primitive datatypes appear on that list, String or any of the wrapper types do not.

I'm still surprised it's allowed.

[admin]

Very good.
String is just a name of a class. It is neither a reserved name or a keyword. It has no special meaning.

HTH,
Paul.

[TwistedLizard]

Thanks Paul.

I'm finding the enthuware question bank & explanations very useful.