About Question enthuware.ocpjp.v8.2.1907 :

[RoyEL1]

I find it a bit curious w.r.t.

Code: Select all

public void outputText(PrintWriter pw, String text) {
         pw.printf(text).print("success"); 
}

that the execution works, but the Java Platform Standard Ed. 8 (JDK SE8) Documentation states that for a PrintWriter, the printf(String format, Objects ... arg) and the printf(Locale l, String format, Objects ... arg) both state that it will throw a NullPointerException if the format string is null.

Is it the case that with only 1 string passed in, the JVM considers the string already formatted?

[admin]

Acutally, the first argument to printf is the format string. So here, it is not the format string that is null but the arg parameter that is null. So there is no reason for it to throw NPE.
It will not write anything to the stream though (because there is no argument to write).

It would be better if changed to pw.printf("%s", text)

HTH,
Paul.

[dameest]

I find it a bit curious w.r.t.

Code: Select all

public void outputText(PrintWriter pw, String text) {
         pw.printf(text).print("success"); 
}

that the execution works, but the Java Platform Standard Ed. 8 (JDK SE8) Documentation states that for a PrintWriter, the printf(String format, Objects ... arg) and the printf(Locale l, String format, Objects ... arg) both state that it will throw a NullPointerException if the format string is null.

Is it the case that with only 1 string passed in, the JVM considers the string already formatted?

For anyone here after 2025, the reason why no NPE is thrown as stated above is because not passing varargs argugment means varargs = empty array, not null.