About Question enthuware.ocajp.i.v7.2.1050 :

[rafaparche]

Hello,

below code iterates only once so I thought that i would be 1 instead 0, why?

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for (i=0 ;       ; i++) break; 

thanks!

[admin]

Iteration doesn't complete because of the break so i++ is never executed.

[madhurisatish]

I want to know what does for ( ; i<5?false:true ; ); mean??

Basically, I have a question like what does for (; i<5;); mean?

Please explain

[madhurisatish]

does it mean it doesn't have body. Is it same like

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for(;i<5;) {
             }

[admin]

does it mean it doesn't have body. Is it same like

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for(;i<5;) {
             }

Yes.

[JuergGogo]

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class TestClass{
   public static void main(String args[]){
      int i = 0;
      for (i=1 ;  i<5  ; i++) continue;  //(1)
      for (i=0 ;       ; i++) ;                                  // break;       //(2)

      for (    ; i<5?false:true ;    );     //(3)   --> compiler error: unreachable statement
   }
}

I have chosen the second Loop as invalid, but it works fine. When eliminating the break statement, you get a compiler error.

[tanushri]

should it compile if the local variable i is being redefined (in the for- loops) within the same scope, ie main method?

[admin]

what happened when you tried it out?

[tanushri]

i didnt run it. But was comparing with Question 8 of test 7.

[flex567]

From the answer:

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A continue statement can occur in and only in a for, while or do-while loop

Is the for each loop included?
In which loop continue cant occur?

[admin]

Yes, it can appear in all loops including enhanced for. Explanation has been updated to make it clear.
thanks!

[crazymind]

Isn't it suppose be an unreachable code error? first loop keep iterates since continue then gets out. Other two inner loops never get executed.

[admin]

No, because the statements use variables that are not compile time constants. That is why the compiler cannot know the value of the loop variables at compile time.

[li_hanglin@bah.com]

In the explanation, it says: for ( ; i<5?false:true ; ); never iterates because i is less than 5 (it is 0 because of //2).

isn't the i in //2 local to that for loop and go out of scope in //3 so for ( ; i<5?false:true ; ) would use the i from int i = 0?

[admin]

No, //2 doesn't contain declaration i.e. int i=0; it contains only assignment i.e. i=0;