public class TestClass{
public static void main(String[] args){
Fo : for(int i = 0; i< 10; i++){
for (int j = 0; j< 10; j++){
if ( i+ j > 10 ) break fo;
}
System.out.println( "hello");
}
}
}
why hello is printed only twice and breaks out of the loop while i debug this on eclipse and suddenly after i=2 it breaks out of the loop, and j can still go till 9th iteration,
please explain in detail its very confusing?
Last edited by admin on Tue Feb 20, 2018 11:16 pm, edited 2 times in total.
Reason:Please put code inside [code] [/code]
When i is 0 or 1, j can go from 0 to 9 without breaking because i+j cannot be > 10 in these cases. This means hello will be printed once when 1 is 0 and second when i is 1. But when i becomes 2, as soon as j becomes 9, break fo; will be executed breaking the outer loop. Hence, the print statement will not be executed.
so that means it will print the statement only when J loop will finish all its iterations and if it doesnt then it will break out of the loop and the statement. is it?
