About Question enthuware.ocajp.i.v7.2.1157 :

[Talel Amira]

Hi,
I correctly answred C, but I did it because I thought that I cannot switch over a boolean. In JLS (14.11): only char, byte, short, int, Character, Byte, Short, Integer, String, or an enum type are permitted.
This is confusing!

[admin]

Not sure why you find it confusing. It is true that you cannot use boolean in a switch but that is not the case here anyway.
-Paul.

[JaredTse]

Hi,

Isn't a switch statement also not supposed to use the boolean data type ?

Thanks

[admin]

That is correct. That is what I said above as well.
-Paul.

[flex567]

These questions is imposible to guess correctly since no book for preparation explains much about what does/doesn't compile.

[crazymind]

Hi, I understand the code inside switch is unreachable but does switch itself cause a compile error without any case or default label? I actually implement this code by removing the "flag = true;" and it compiles ok. So switch doesn't cause a compile error. It is ok to has no case or default label and without any code inside the block?

[admin]

Yes, if you have code inside a switch then that has to be associated with a case or default label. The explanation also explains the same.
Empty switch is fine as you already found out.

[enthunoob]

I thought it wouldn't compile cause variables i and flag are declared in the loop blocks and therefor not available outside of them.