About Question enthuware.ocajp.i.v7.2.1154 :

[bptoth]

The explanation regarding the int,int answer says as follows

a*10/4.0; generates a double so, A2's m1() cannot return an int. ( It will need a cast otherwise: return (int) a*10/4.0; )

However, with this form of casting there still seems to be compilation error (cannot convert from double to int)
My understanding is that since the casting operator precedence is higher than that of * and / operators, thus it only concerns 'a' (which is already an int) and then there is int divided by double again

So I suppose it should be return (int) (a*10/4.0); with parentheses?

[admin]

You are right. This has now been fixed. Thank you for your feedback!
Paul.