About Question enthuware.ocajp.i.v7.2.870 :

[vchhang]

According to the explanation as I understand it, option#3 is correct but yet it is not. Please explain.

Except:
size() method of ArrayList returns the number of elements. Here, it returns 2. Since numbering in ArrayList starts with 0. al.get(2) will cause an IndexOutOfBoundsException to be thrown because only 0 and 1 are valid indexes for a list of size 2.

[admin]

It seems to be because of the same repaint problem that you reported earlier. Please see attached image.

[JuergGogo]

Code: Select all

ArrayList<String> al = new ArrayList<String>();

This ArrayList can be declared also like: ArrayList<String> al = new ArrayList<>();

[admin]

Code: Select all

ArrayList<String> al = new ArrayList<String>();

This ArrayList can be declared also like: ArrayList<String> al = new ArrayList<>();

Yes, it can be.